Statistics for Business & Economics, Revised, 13th Edition by David R. Anderson – Test Bank

Complete Test Bank With Answers

 

 

Sample Questions Posted Below

 

CH 05 – Discrete Probability Distributions

1. Which of the following is a characteristic of an experiment where the binomial probability distribution is applicable?

a. The experiment has at least two possible outcomes

b. Exactly two outcomes are possible on each trial

c. The trials are dependent on each other

d. The probabilities of the outcomes changes from one trial

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

2. A numerical description of the outcome of an experiment is called a

a. descriptive statistic.

b. probability function.

c. variance.

d. random variable.

ANSWER: d

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.01 – Random Variables

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

3. A probability distribution showing the probability of x successes in n trials, where the probability of success does not

change from trial to trial, is termed a

a. uniform probability distribution.

b. binomial probability distribution.

c. hypergeometric probability distribution.

d. normal probability distribution.

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

4. A continuous random variable may assume

a. any numerical value in an interval or collection of intervals.

b. finite number of values in a collection of intervals.

c. an infinite sequence of values.

Copyright Cengage Learning. Powered by Cognero. Page 1CH 05 – Discrete Probability Distributions

d. only the positive integer values in an interval.

ANSWER: a

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.01 – Random Variables

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

5. A description of the distribution of the values of a random variable and their associated probabilities is called a

a. probability distribution.

b. empirical discrete distribution.

c. bivariate distribution.

d. table of binomial probability.

ANSWER: a

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

6. Which of the following is a required condition for a discrete probability function?

a. ∑f(x) = 0 for all values of x

b. f(x) 1 for all values of x

c. f(x) < 0 for all values of x

d. ∑f(x) = 1 for all values of x

ANSWER: d

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

7. A measure of the average value of a random variable is called a(n)

a. variance.

b. standard deviation.

c. expected value.

d. coefficient of variation.

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: Copyright Cengage Learning. Powered by Cognero. BSST.ASWC.17.05.03 – Expected Value and Variance

Page 2CH 05 – Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

8. Which of the following is a required condition for a discrete probability function?

a. f(x) 0 for all values of x

b. ∑f(x) = 1 for all values of x

c. ∑f(x) = 0 for all values of x

d. ∑f(x) 1 for all values of x

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

9. A weighted average of the values of a random variable, where the probability function provides weights, is known as

a. the probable value.

b. the median value.

c. the expected value.

d. the variance.

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

10. An experiment consists of determining the speed of automobiles on a highway by the use of radar equipment. The

random variable in this experiment is a

a. discrete random variable.

b. continuous random variable.

c. mixed type random variable.

d. multivariate random variable.

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.01 – Random Variables

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

Copyright Cengage Learning. Powered by Cognero. Page 3CH 05 – Discrete Probability Distributions

11. The number of customers that enter a store during one day is an example of

a. a continuous random variable.

b. a discrete random variable.

c. either a continuous or a discrete random variable, depending on whether odd or even number of the customers

enter.

d. either a continuous or a discrete random variable, depending on the gender of the customers.

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.01 – Random Variables

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

12. The weight of an object is an example of

a. a continuous random variable.

b. a discrete random variable.

c. either a continuous or a discrete random variable, depending on the nature of the object.

d. either a continuous or a discrete random variable, depending on the unit of measurement.

ANSWER: a

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.01 – Random Variables

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

13. Four percent of the customers of a mortgage company default on their payments. A sample of five customers is

selected. What is the probability that exactly two customers in the sample will default on their payments?

a. 0.2592

b. 0.0142

c. 0.9588

d. 0.7408

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

14. Twenty percent of the students in a class of 100 are planning to go to graduate school. The standard deviation of this

binomial distribution is

a. 20.

b. 16.

Copyright Cengage Learning. Powered by Cognero. Page 4CH 05 – Discrete Probability Distributions

c. 4.

d. 2.

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

15. In the textile industry, a manufacturer is interested in the number of blemishes or flaws occurring in each 100 feet of

material. The probability distribution that has the greatest chance of applying to this situation is the

a. Normal distribution.

b. Binomial distribution.

c. Poisson distribution.

d. Uniform distribution.

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.06 – Poisson Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

16. The Poisson probability distribution is a

a. continuous probability distribution.

b. discrete probability distribution.

c. uniform probability distribution.

d. normal probability distribution.

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.06 – Poisson Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

17. The binomial probability distribution is used with

a. a continuous random variable.

b. a discrete random variable.

c. a uniform random variable.

d. an intermittent random variable.

ANSWER: b

POINTS: 1

Copyright Cengage Learning. Powered by Cognero. Page 5CH 05 – Discrete Probability Distributions

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

18. The expected value of a discrete random variable

a. is the most likely or highest probability value for the random variable.

b. will always be one of the values x can take on, although it may not be the highest probability value for the

random variable.

c. is the average value for the random variable over many repeats of the experiment.

d. is the value it is expected to assume in the next trial.

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

19. Which of the following is not a characteristic of an experiment where the binomial probability distribution is

applicable?

a. The experiment has a sequence of n identical trials

b. Exactly two outcomes are possible on each trial

c. The trials are dependent

d. The probabilities of the outcomes do not change from one trial to another

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

20. The expected value of a random variable is

a. the value of the random variable that should be observed on the next repeat of the experiment

b. the value of the random variable that occurs most frequently

c. the square root of the variance

d. None of these alternatives is correct.

ANSWER: d

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

Copyright Cengage Learning. Powered by Cognero. Page 6CH 05 – Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

21. Which of the following is not a property of a binomial experiment?

a. The experiment consists of a sequence of n identical trials

b. Each outcome can be referred to as a success or a failure

c. The probabilities of the two outcomes can change from one trial to the next

d. The trials are independent

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

22. In a binomial experiment

a. the probability does not change from trial to trial.

b. the probability changes from trial to trial.

c. the probability could change from trial to trial, depending on the situation under consideration.

d. the probability could change depending on the number of outcomes.

ANSWER: a

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

23. The Poisson probability distribution is used with

a. a continuous random variable.

b. a discrete random variable.

c. either a continuous or discrete random variable.

d. any random variable.

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.06 – Poisson Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

Copyright Cengage Learning. Powered by Cognero. Page 7CH 05 – Discrete Probability Distributions

24. The variance Var(x) for the binomial distribution is given by equation

a. np(n – 1).

b. np(1 – np).

c. n(1 – p).

d. np(1 – p).

ANSWER: d

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

25. The expected value for a binomial distribution is given by equation

a. (n – 1)(1 – p).

b. n(1 – p).

c. np.

d. (n – 1)p.

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

26. A production process produces 2% defective parts. A sample of five parts from the production process is selected.

What is the probability that the sample contains exactly two defective parts?

a. 0.0004

b. 0.0038

c. 0.10

d. 0.02

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

27. When dealing with the number of occurrences of an event over a specified interval of time or space, the appropriate

probability distribution is a

a. Binomial distribution.

b. Poisson distribution.

Copyright Cengage Learning. Powered by Cognero. Page 8CH 05 – Discrete Probability Distributions

c. Normal distribution.

d. Hypergeometric probability distribution.

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.06 – Poisson Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

28. The key difference between the binomial and hypergeometric distribution is that, with the hypergeometric distribution

a. the probability of success must be less than 0.5.

b. the probability of success changes from trial to trial.

c. the trials are independent of each other.

d. the random variable is continuous.

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.07 – Hypergeometric Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

29. Assume that you have a binomial experiment with p = 0.4 and a sample size of 50. The variance of this distribution is

a. 20.

b. 12.

c. 3.46.

d. 144.

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

30. In a binomial experiment the probability of success is 0.06. What is the probability of two successes in seven trials?

a. 0.0036

b. 0.0600

c. 0.0555

d. 0.2800

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

Copyright Cengage Learning. Powered by Cognero. Page 9CH 05 – Discrete Probability Distributions

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

31. Random variable x has the probability function f(x) = X/6, for x = 1, 2 or 3

The expected value of x is

a. 0.333.

b. 0.500.

c. 2.000.

d. 2.333.

ANSWER: d

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

32. A random variable that may take on any value in an interval or collection of intervals is known as a

a. continuous random variable.

b. discrete random variable.

c. mixed type random variable.

d. multivariate random variable.

ANSWER: a

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.01 – Random Variables

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

33. The following represents the probability distribution for the daily demand of computers at a local store.

Demand Probability

0 0.1

1 0.2

2 0.3

3 0.2

4 0.2

The expected daily demand is

a. 1.0

b. 2.2

c. 2.0

d. 4.0

Copyright Cengage Learning. Powered by Cognero. Page 10CH 05 – Discrete Probability Distributions

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

34. The following represents the probability distribution for the daily demand of computers at a local store.

Demand Probability

0 0.1

1 0.2

2 0.3

3 0.2

4 0.2

The probability of having a demand for at least two computers is

a. 0.7

b. 0.3

c. 0.4

d. 1.0

ANSWER: a

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

35. The student body of a large university consists of 60% female students. A random sample of 8 students is selected.

What is the probability that among the students in the sample exactly two are female?

a. 0.0896

b. 0.2936

c. 0.0413

d. 0.0007

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

36. The student body of a large university consists of 60% female students. What is the probability that among the students in the sample at least 7 are female?

A random sample of 8 students is selected.

Copyright Cengage Learning. Powered by Cognero. Page 11CH 05 – Discrete Probability Distributions

a. 0.1064

b. 0.0896

c. 0.0168

d. 0.8936

ANSWER: a

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

37. The student body of a large university consists of 60% female students. A random sample of 8 students is selected.

What is the probability that among the students in the sample at least 6 are male?

a. 0.0413

b. 0.0079

c. 0.0007

d. 0.0499

ANSWER: d

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

38. Roth is a computer-consulting firm. The number of new clients that they have obtained each month has ranged from 0

to 6. The number of new clients has the probability distribution that is shown below.

Number of

New Clients Probability

0 0.05

1 0.10

2 0.15

3 0.35

4 0.20

5 0.10

6 0.05

The expected number of new clients per month is

a. 6

b. 0

c. 3.05

d. 21

ANSWER: c

POINTS: 1

Copyright Cengage Learning. Powered by Cognero. Page 12CH 05 – Discrete Probability Distributions

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

39. Roth is a computer-consulting firm. The number of new clients that they have obtained each month has ranged from 0

to 6. The number of new clients has the probability distribution that is shown below.

Number of

New Clients Probability

0 0.05

1 0.10

2 0.15

3 0.35

4 0.20

5 0.10

6 0.05

The variance is

a. 1.431

b. 2.047

c. 3.05

d. 21

ANSWER: b

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

40. Roth is a computer-consulting firm. The number of new clients that they have obtained each month has ranged from 0

to 6. The number of new clients has the probability distribution that is shown below.

Number of

New Clients Probability

0 0.05

1 0.10

2 0.15

3 0.35

4 0.20

5 0.10

6 0.05

The standard deviation is

a. 1.431

b. 2.047

c. 3.05

Copyright Cengage Learning. Powered by Cognero. Page 13CH 05 – Discrete Probability Distributions

d. 21

ANSWER: a

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

41. Forty percent of all registered voters in a national election are female. A random sample of 5 voters is selected.

The probability that the sample contains 2 female voters is

a. 0.0778

b. 0.7780

c. 0.5000

d. 0.3456

ANSWER: d

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

42. Forty percent of all registered voters in a national election are female. A random sample of 5 voters is selected. probability that there are no females in the sample is

a. 0.0778

b. 0.7780

c. 0.5000

d. 0.3456

ANSWER: a

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

The

43. Consider the probability distribution below.

x f(x)

10 .2

20 .3

30 .4

40 .1

The expected value of x equals

a. 24

Copyright Cengage Learning. Powered by Cognero. Page 14CH 05 – Discrete Probability Distributions

b. 25

c. 30

d. 100

ANSWER: a

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

44. Consider the probability distribution below.

x f(x)

10 .2

20 .3

30 .4

40 .1

The variance of x equals

a. 9.165

b. 84

c. 85

d. 93.33

ANSWER: b

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

45. A sample of 2,500 people was asked how many cups of coffee they drink in the morning. You are given the following

sample information.

Cups of Coffee Frequency

0 700

1 900

2 600

3 300

2,500

The expected number of cups of coffee is

a. 1

b. 1.2

c. 1.5

d. 1.7

ANSWER: b

POINTS: 1

Copyright Cengage Learning. Powered by Cognero. Page 15CH 05 – Discrete Probability Distributions

DIFFICULTY: Moderate

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

46. A sample of 2,500 people was asked how many cups of coffee they drink in the morning. You are given the following

sample information.

Cups of Coffee Frequency

0 700

1 900

2 600

3 300

2,500

The variance of the number of cups of coffee is

a. .96

b. .9798

c. 1

d. 2.4

ANSWER: a

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

47. The probability that Pete will catch fish when he goes fishing is .8. Pete is going to fish 3 days next week. Define the

random variable x to be the number of days Pete catches fish. The probability that Pete will catch fish on exactly one day

is

a. .008

b. .096

c. .104

d. .8

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

48. The probability that Pete will catch fish when he goes fishing is .8. Pete is going to fish 3 days next week. Define the

random variable x to be the number of days Pete catches fish. The probability that Pete will catch fish on one day or less

is

Copyright Cengage Learning. Powered by Cognero. Page 16CH 05 – Discrete Probability Distributions

a. .008

b. .096

c. .104

d. .8

ANSWER: c

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

49. The probability that Pete will catch fish when he goes fishing is .8. Pete is going to fish 3 days next week. Define the

random variable x to be the number of days Pete catches fish. The expected number of days Pete will catch fish is

a. .6

b. .8

c. 2.4

d. 3

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

50. The probability that Pete will catch fish when he goes fishing is .8. Pete is going to fish 3 days next week. Define the

random variable x to be the number of days Pete catches fish. The variance of the number of days Pete will catch fish is

a. .16

b. .48

c. .8

d. 2.4

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

51. The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that

the probability of an occurrence is the same in any two-time periods of an equal length. It is known that the mean number

of occurrences in ten minutes is 5.3. Which of the following discrete probability distributions’ properties are satisfied by

random variable x?

Copyright Cengage Learning. Powered by Cognero. Page 17CH 05 – Discrete Probability Distributions

a. Normal

b. Poisson

c. Binomial

d. Hypergeometric

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.06 – Poisson Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

52. The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that

the probability of an occurrence is the same in any two-time periods of an equal length. It is known that the mean number

of occurrences in ten minutes is 5.3. The appropriate probability distribution for the random variable is

a. discrete.

b. continuous.

c. either discrete or continuous depending on how the interval is defined.

d. binomial.

ANSWER: a

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.06 – Poisson Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

53. The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that

the probability of an occurrence is the same in any two-time periods of an equal length. It is known that the mean number

of occurrences in ten minutes is 5.3. The expected value of the random variable x is

a. 2.

b. 5.3.

c. 10.

d. 2.30.

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.06 – Poisson Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

54. The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that

the probability of an occurrence is the same in any two-time periods of an equal length. It is known that the mean number

of occurrences in ten minutes is 5.3. The probability that there are 8 occurrences in ten minutes is

Copyright Cengage Learning. Powered by Cognero. Page 18CH 05 – Discrete Probability Distributions

a. .0241

b. .0771

c. .1126

d. .9107

ANSWER: b

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES: BSST.ASWC.17.05.06 – Poisson Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

55. The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that

the probability of an occurrence is the same in any two-time periods of an equal length. It is known that the mean number

of occurrences in ten minutes is 5.3. The probability that there are less than 3 occurrences is

a. .0659

b. .0948

c. .1016

d. .1239

ANSWER: c

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES: BSST.ASWC.17.05.06 – Poisson Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

56. The probability distribution for the daily sales at Michael’s Co. is given below.

Daily Sales

(In $1,000s) Probability

40 0.1

50 0.4

60 0.3

70 0.2

The probability of having sales of no more than $60,000 is

a. 0.7

b. 0.2

c. 0.8

d. 0.5

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

Copyright Cengage Learning. Powered by Cognero. Page 19CH 05 – Discrete Probability Distributions

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

57. The probability distribution for the daily sales at Michael’s Co. is given below.

Daily Sales

(In $1,000s) Probability

40 0.1

50 0.4

60 0.3

70 0.2

The probability of having sales of at least $50,000 is

a. 0.5

b. 0.10

c. 0.30

d. 0.90

ANSWER: d

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

58. The probability distribution for the number of goals the Lions soccer team makes per game is given below.

Number

Of Goals Probability

0 0.05

1 0.15

2 0.35

3 0.30

4 0.15

What is the probability that in a given game the Lions will score at least 1 goal?

a. 0.20

b. 0.55

c. 1.0

d. 0.95

ANSWER: d

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

59.

Copyright Cengage Learning. Powered by Cognero. Page 20CH 05 – Discrete Probability Distributions

Oriental Reproductions, Inc. is a company that produces handmade carpets with oriental designs. The production records

show that the monthly production has ranged from 1 to 5 carpets. The production levels and their respective probabilities

are shown below.

Production

Per Month Probability

1 0.01

2 0.04

3 0.10

4 0.80

5 0.05

The expected monthly production level is

a. 1.00

b. 4.00

c. 3.00

d. 3.84

ANSWER: d

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

60. Oriental Reproductions, Inc. is a company that produces handmade carpets with oriental designs. The production

records show that the monthly production has ranged from 1 to 5 carpets. The production levels and their respective

probabilities are shown below.

Production

Per Month Probability

1 0.01

2 0.04

3 0.10

4 0.80

5 0.05

The standard deviation for the production is

a. 4.32

b. 3.74

c. 0.374

d. 0.612

ANSWER: d

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

Copyright Cengage Learning. Powered by Cognero. Page 21CH 05 – Discrete Probability Distributions

61. Thirty-two percent of the students in a management class are graduate students. A random sample of 5 students is

selected. Using the binomial probability function, determine the probability that the sample contains exactly 2 graduate

students? (Round to three decimal places.)

ANSWER: 0.322 (rounded)

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

62. Seventy percent of the students applying to a university are accepted. Using the binomial probability tables, what is

the probability that among the next 18 applicants

a. At least 6 will be accepted?

b. Exactly 10 will be accepted?

c. Exactly 5 will be rejected?

d. Fifteen or more will be accepted?

e. Determine the expected number of acceptances.

f. Compute the standard deviation.

ANSWER:

a. 0.9986

b. 0.0811

c. 0.2017

d. 0.1646

e. 12.6

f. 1.9442

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

63. General Hospital has noted that they admit an average of 8 patients per hour.

a. b. What is the probability that during the next hour less than 3 patients will be admitted?

What is the probability that during the next two hours exactly 8 patients will be admitted?

ANSWER:

a. 0.0137

b. 0.0120

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES

:

BSST.ASWC.17.05.06 – Poisson Probability Distribution

Copyright Cengage Learning. Powered by Cognero. Page 22CH 05 – Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

64. The demand for a product varies from month to month. Based on the past year’s data, the following probability

distribution shows MNM company’s monthly demand.

x f(x)

Unit Demand Probability

0 0.10

1,000 0.10

2,000 0.30

3,000 0.40

4,000 0.10

a. b. Determine the expected number of units demanded per month.

Each unit produced costs the company $8.00, and is sold for $10.00. How much will the company gain or lose in a

month if they stock the expected number of units demanded, but sell 2000 units?

ANSWER:

a. 2300

b. Profit = $1600

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.03 – Expected Value and Variance

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

65. Twenty-five percent of the employees of a large company are minorities. A random sample of 7 employees is selected.

a. b. c. d. e. What is the probability that the sample contains exactly 4 minorities?

What is the probability that the sample contains fewer than 2 minorities?

What is the probability that the sample contains exactly 1 non-minority?

What is the expected number of minorities in the sample?

What is the variance of the minorities?

ANSWER:

a. 0.0577

b. 0.4450

c. 0.0013

d. 1.75

e. 1.3125

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

Copyright Cengage Learning. Powered by Cognero. Page 23CH 05 – Discrete Probability Distributions

66. A salesperson contacts eight potential customers per day. From past experience, we know that the probability of a

potential customer making a purchase is .10.

a. b. c. d. What is the probability that the salesperson will make at least exactly two sales in a day?

What is the probability that the salesperson will make at least two sales in a day?

What percentage of days will the salesperson not make a sale?

What is the expected number of sales per day?

ANSWER:

a. 0.1488

b. 0.1869

c. 43.05%

d. 0.8

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

67. A life insurance company has determined that each week an average of seven claims is filed in its Nashville branch.

a. b. c. d. What is the probability that during the next week exactly seven claims will be filed?

What is the probability that during the next week no claims will be filed?

What is the probability that during the next week fewer than four claims will be filed?

What is the probability that during the next week at least seventeen claims will be filed?

ANSWER:

a. 0.1490

b. 0.0009

c. 0.0817

d. 0.0009

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.06 – Poisson Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

68. When a particular machine is functioning properly, 80% of the items produced are non-defective. If three items are

examined, what is the probability that one is defective? Use the binomial probability function to answer this question.

ANSWER: 0.384

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

Copyright Cengage Learning. Powered by Cognero. Page 24CH 05 – Discrete Probability Distributions

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

69. Ten percent of the items produced by a machine are defective. Out of 15 items chosen at random,

a. b. c. what is the probability that exactly 3 items will be defective?

what is the probability that less than 3 items will be defective?

what is the probability that exactly 11 items will be non-defective?

ANSWER:

a. 0.1285

b. 0.816

c. 0.0428

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

70. The student body of a large university consists of 30% Business majors. A random sample of 20 students is selected.

a. b. c. d. What is the probability that among the students in the sample at least 10 are Business majors?

What is the probability that at least 16 are not Business majors?

What is the probability that exactly 10 are Business majors?

What is the probability that exactly 12 are not Business majors?

ANSWER:

a. 0.0479

b. 0.2374

c. 0.0308

d. 0.1144

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

71. Shoppers enter Hamilton Place Mall at an average of 120 per hour.

a. What is the probability that exactly 5 shoppers will enter the mall between noon and 12:05 p.m.?

b. What is the probability that at least 35 shoppers will enter the mall between 5:00 and 5:10 p.m.?

ANSWER:

a. 0.0378

b. 0.0015

POINTS: 1

Copyright Cengage Learning. Powered by Cognero. Page 25CH 05 – Discrete Probability Distributions

DIFFICULTY: Moderate

LEARNING OBJECTIVES

BSST.ASWC.17.05.06 – Poisson Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

72. A production process produces 90% non-defective parts. A sample of 10 parts from the production process is

selected.

a. b. c. d. ANSWER:

What is the probability that the sample will contain 7 non-defective parts?

What is the probability that the sample will contain at least 4 defective parts?

What is the probability that the sample will contain less than 5 non–defective parts?

What is the probability that the sample will contain no defective parts?

a. 0.0574

b. 0.0128

c. 0.0001

d. 0.3487

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

73. Fifty-five percent of the applications received for a particular credit card are accepted. Among the next twelve

applications,

a. b. c. d. e. what is the probability that all will be rejected?

what is the probability that all will be accepted?

what is the probability that exactly 4 will be accepted?

what is the probability that fewer than 3 will be accepted?

Determine the expected number and the variance of the accepted applications.

ANSWER:

a. 0.0001

b. 0.0008

c. 0.0762

d. 0.0079

e. 6.60; 2.9700

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: Copyright Cengage Learning. Powered by Cognero. United States – AK – DISC: Probability Distributions

Page 26CH 05 – Discrete Probability Distributions

KEYWORDS: Bloom’s: Apply

74. The probability distribution of the daily demand for a product is shown below.

Demand Probability

0 0.05

1 0.10

2 0.15

3 0.35

4 0.20

5 0.10

6 0.05

a. b. ANSWER:

What is the expected number of units demanded per day?

Determine the variance and the standard deviation.

a. 3.05

b. variance = 2.0475 std. dev. = 1.431

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES

BSST.ASWC.17.05.03 – Expected Value and Variance

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

75. In a large corporation, 65% of the employees are male. A random sample of five employees is selected. Use the

Binomial probability tables to answer the following questions.

a. b. c. d. What is the probability that the sample contains exactly three male employees?

What is the probability that the sample contains no male employees?

What is the probability that the sample contains more than three female employees?

What is the expected number of female employees in the sample?

ANSWER:

a. 0.3364

b. 0.0053

c. 0.0541

d. 1.75

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

76. For the following probability distribution:

x f(x)

Copyright Cengage Learning. Powered by Cognero. Page 27CH 05 – Discrete Probability Distributions

0 0.01

1 0.02

2 0.10

3 0.35

4 0.20

5 0.11

6 0.08

7 0.05

8 0.04

9 0.03

10 0.01

a. Determine E(x).

b. ANSWER:

Determine the variance and the standard deviation.

a. 4.14

b. variance = 3.7 std. dev. = 1.924

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES

BSST.ASWC.17.05.03 – Expected Value and Variance

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

77. A random variable x has the following probability distribution:

x f(x)

0 0.08

1 0.17

2 0.45

3 0.25

4 0.05

a. Determine the expected value of x.

b. Determine the variance.

ANSWER:

a. 2.02

b. 0.9396

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES

BSST.ASWC.17.05.03 – Expected Value and Variance

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

78. A company sells its products to wholesalers in batches of 1,000 units only. The daily demand for its product and the

Copyright Cengage Learning. Powered by Cognero. Page 28CH 05 – Discrete Probability Distributions

respective probabilities are given below.

Demand (Units) Probability

0 0.2

1000 0.2

2000 0.3

3000 0.2

4000 0.1

a. b. ANSWER:

Determine the expected daily demand.

Assume that the company sells its product at $3.75 per unit. What is the expected daily revenue?

a. 1800

b. $6,750

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES

BSST.ASWC.17.05.03 – Expected Value and Variance

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

79. The records of a department store show that 20% of its customers who make a purchase, return the merchandise in

order to exchange it. In the next six purchases,

a. b. c. what is the probability that three customers will return the merchandise for exchange?

what is the probability that four customers will return the merchandise for exchange?

what is the probability that none of the customers will return the merchandise for exchange?

ANSWER:

a. 0.0819

b. 0.0154

c. 0.2621

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

80. In a large university, 15% of the students are female. If a random sample of twenty students is selected,

a. b. c. d. e. f. what is the probability that the sample contains exactly four female students?

what is the probability that the sample will contain no female students?

what is the probability that the sample will contain exactly twenty female students?

what is the probability that the sample will contain more than nine female students?

what is the probability that the sample will contain fewer than five female students?

what is the expected number of female students?

Copyright Cengage Learning. Powered by Cognero. Page 29CH 05 – Discrete Probability Distributions

ANSWER:

a. 0.1821

b. 0.0388

c. 0.0000

d. 0.0002

e. 0.8298

f. 3

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

81. In a southern state, it was revealed that 5% of all automobiles in the state did not pass inspection. Of the next ten

automobiles entering the inspection station,

a. b. c. d. e. f. g. what is the probability that none will pass inspection?

what is the probability that all will pass inspection?

what is the probability that exactly two will not pass inspection?

what is the probability that more than three will not pass inspection?

what is the probability that fewer than two will not pass inspection?

Find the expected number of automobiles not passing inspection.

Determine the standard deviation for the number of cars not passing inspection.

ANSWER:

a. 0.0000

b. 0.5987

c. 0.0746

d. 0.0011

e. 0.9138

f. 0.5

g. 0.6892

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

82. The random variable x has the following probability distribution:

x f(x)

0 .25

1 .20

2 .15

3 .30

4 .10

Copyright Cengage Learning. Powered by Cognero. Page 30CH 05 – Discrete Probability Distributions

a. b. c. d. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.

Calculate the expected value of x.

Calculate the variance of x.

Calculate the standard deviation of x.

ANSWER:

a. yes f(x) 0 and ∑ f(x) = 1

b. 1.8

c. 1.86

d. 1.364

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTI

BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

VES:

BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDA

United States – BUSPROG: Analytic

RDS:

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply | Bloom’s: Understand

83. The probability function for the number of insurance policies John will sell to a customer is given by

f(X) = .5 – (X/6) for X = 0, 1, or 2

a. b. c. d. e. Is this a valid probability function? Explain your answer.

What is the probability that John will sell exactly 2 policies to a customer?

What is the probability that John will sell at least 2 policies to a customer?

What is the expected number of policies John will sell?

What is the variance of the number of policies John will sell?

ANSWER:

a. yes f(x) 0 and ∑ f(x) = 1

b. 0.167

c. 0.167

d. 0.667

e. 0.556

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTI

BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

VES:

BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDA

United States – BUSPROG: Analytic

RDS:

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply | Bloom’s: Understand

84. The probability distribution for the rate of return on an investment is

Rate of Return

(In Percent) Probability

9.5 .1

Copyright Cengage Learning. Powered by Cognero. Page 31CH 05 – Discrete Probability Distributions

9.8 .2

10.0 .3

10.2 .3

10.6 .1

a. b. c. ANSWER:

What is the probability that the rate of return will be at least 10%?

What is the expected rate of return?

What is the variance of the rate of return?

a. 0.7

b. 10.03

c. 0.0801

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTI

BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

VES:

BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDA

United States – BUSPROG: Analytic

RDS:

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

85. In a large university, 75% of students live in dormitories. A random sample of 5 students is selected. Use the binomial

probability tables to answer the following questions.

a. b. c. d. What is the probability that the sample contains exactly three students who live in the dormitories?

What is the probability that the sample contains no students who lives in the dormitories?

What is the probability that the sample contains more than three students who do not live in the dormitories?

What is the expected number of students (in the sample) who do not live in the dormitories?

ANSWER:

a. 0.2637

b. 0.001

c. 0.0156

d. 1.25

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

86. A manufacturing company has 5 identical machines that produce nails. The probability that a machine will break

down on any given day is .1. Define a random variable X to be the number of machines that will break down in a day.

a. b. c. d. e. What is the appropriate probability distribution for X?

Compute the probability that 4 machines will break down.

Compute the probability that at least 4 machines will break down.

What is the expected number of machines that will break down in a day?

What is the variance of the number of machines that will break down in a day?

Copyright Cengage Learning. Powered by Cognero. Page 32CH 05 – Discrete Probability Distributions

ANSWER:

a. Binomial

b. 0.00045

c. 0.00046

d. 0.5

e. 0.45

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: United States – AK – DISC: Probability Distributions

Bloom’s: Apply | Bloom’s: Understand

87. On the average, 6.7 cars arrive at the drive-up window of a bank every hour. Define the random variable x to be the

number of cars arriving in any hour.

a. b. c. What is the appropriate probability distribution for x? Explain how x satisfies the properties of the distribution.

Compute the probability that exactly 5 cars will arrive in the next hour.

Compute the probability that no more than 5 cars will arrive in the next hour.

ANSWER:

a. b. 0.1385

c. 0.3406

Poisson; it shows the probability of x occurrences of the event over a time period.

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES

BSST.ASWC.17.05.06 – Poisson Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: United States – AK – DISC: Probability Distributions

Bloom’s: Apply | Bloom’s: Understand

88. Twenty-five percent of all resumes received by a corporation for a management position are from females. Fifteen

resumes will be received tomorrow.

a. b. c. d. What is the probability that exactly 5 of the resumes will be from females?

What is the probability that fewer than 3 of the resumes will be from females?

What is the expected number of resumes from women?

What is the variance of the number of resumes from women?

ANSWER:

a. 0.1651

b. 0.2361

c. 3.75

d. 2.8125

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

Copyright Cengage Learning. Powered by Cognero. Page 33CH 05 – Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

89. The average number of calls received by a switchboard in a 30-minute period is 15.

a. b. What is the probability that between 10:00 and 10:30 the switchboard will receive exactly 10 calls?

What is the probability that between 10:00 and 10:30 the switchboard will receive more than 9 calls but fewer than

15 calls?

c. What is the probability that between 10:00 and 10:30 the switchboard will receive fewer than 7 calls?

ANSWER:

a. 0.0486

b. 0.3958

c. 0.0075

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.06 – Poisson Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

90. Two percent of the parts produced by a machine are defective. Twenty parts are selected at random. Use the binomial

probability tables to answer the following questions.

a. b. c. d. e. What is the probability that exactly 3 parts will be defective?

What is the probability that the number of defective parts will be more than 2 but fewer than 6?

What is the probability that fewer than 4 parts will be defective?

What is the expected number of defective parts?

What is the variance for the number of defective parts?

ANSWER:

a. 0.0065

b. 0.0071

c. 0.9974

d. 0.4

e. 0.392

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

91. Compute the hypergeometric probabilities for the following values of n and x. Assume N = 8 and r = 5.

a. n = 5, x = 2

Copyright Cengage Learning. Powered by Cognero. Page 34CH 05 – Discrete Probability Distributions

b. c. d. n = 6, x = 4

n = 3, x = 0

n = 3, x = 3

ANSWER:

a. 0.1786

b. 0.5357

c. 0.01786

d. 0.1786

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.07 – Hypergeometric Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

92. Seven students have applied for merit scholarships. This year 3 merit scholarships were awarded. If a random sample

of 3 applications (from the population of 7) is selected,

a. b. what is the probability that 2 students were recipients of scholarships?

what is the probability that no students were the recipients of scholarship?

ANSWER:

a. 0.2143

b. 0.1143

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

93. Determine the probability of being dealt 4 kings in a 5-card poker hand.

ANSWER: 120/6,497,400 = 0.00001847

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES: BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

94. Twenty percent of the applications received for a particular position are rejected. What is the probability that among

the next fourteen applications,

a. none will be rejected?

b. all will be rejected?

c. less than 2 will be rejected?

Copyright Cengage Learning. Powered by Cognero. Page 35CH 05 – Discrete Probability Distributions

d. e. more than four will be rejected?

Determine the expected number of rejected applications and its variance.

ANSWER:

a. 0.0440

b. 0.0000

c. 0.1979

d. 0.1297

e. 2.8, 2.24

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

95. An insurance company has determined that each week an average of nine claims are filed in their Atlanta branch.

What is the probability that during the next week

a. b. c. d. exactly seven claims will be filed?

no claims will be filed?

less than four claims will be filed?

at least eighteen claims will be filed?

ANSWER:

a. 0.1171

b. 0.0001

c. 0.0212

d. 0.0053

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.06 – Poisson Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

96. A local university reports that 10% of their students take their general education courses on a pass/fail basis. Assume

that fifteen students are registered for a general education course.

a. b. c. d. What is the expected number of students who have registered on a pass/fail basis?

What is the probability that exactly five are registered on a pass/fail basis?

What is the probability that more than four are registered on a pass/fail basis?

What is the probability that less than two are registered on a pass/fail basis?

ANSWER:

a. 1.5

b. 0.01050

c. 0.0127

d. 0.5491

POINTS: 1

Copyright Cengage Learning. Powered by Cognero. Page 36CH 05 – Discrete Probability Distributions

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.05 – Binomial Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

97. Only 0.02% of credit card holders of a company report the loss or theft of their credit cards each month. The company

has 15,000 credit cards in the city of Memphis. Use the Poisson probability tables to answer the following questions.

What is the probability that during the next month in the city of Memphis

a. b. c. d. e. f. no one reports the loss or theft of his or her credit cards?

every credit card is lost or stolen?

six people report the loss or theft of their cards?

at least nine people report the loss or theft of their cards?

Determine the expected number of reported lost or stolen credit cards.

Determine the standard deviation for the number of reported lost or stolen cards.

ANSWER:

a. 0.0498

b. 0.0000

c. 0.0504

d. 0.0038

e. 3

f. 1.73

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.06 – Poisson Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

98. A production process produces 2% defective parts. A sample of 5 parts from the production is selected. What is the

probability that the sample contains exactly two defective parts? Use the binomial probability function and show your

computations to answer this question.

ANSWER: 0.0037648

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

99. A retailer of electronic equipment received six VCRs from the manufacturer. Three of the VCRs were damaged in the

shipment. The retailer sold two VCRs to two customers.

a. Can a binomial formula be used for the solution of the above problem?

Copyright Cengage Learning. Powered by Cognero. Page 37CH 05 – Discrete Probability Distributions

b. c. d. What kind of probability distribution does the above satisfy, and is there a function for solving such problems?

What is the probability that both customers received damaged VCRs?

What is the probability that one of the two customers received a defective VCR?

ANSWER:

a. No, in a binomial experiment, trials are independent of each other.

b. Hypergeometric probability distribution

c. 0.2

d. 0.6

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.07 – Hypergeometric Probability Distribution

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: United States – AK – DISC: Probability Distributions

Bloom’s: Apply | Bloom’s: Understand

100. The management of a grocery store has kept a record of bad checks received per day for a period of 200 days. The

data are shown below.

Number of Bad

Checks Received Number of Days

0 8

1 12

2 20

3 60

4 40

5 30

6 20

7 10

a. b. c. d. e. Develop a probability distribution for the above data.

Is the probability distribution that you found in Part “a” a proper probability distribution? Explain.

Determine the cumulative probability distribution f(x).

What is the probability that in a given day the store receives four or less bad checks?

What is the probability that in a given day the store receives more than 3 bad checks?

ANSWER:

a. c.

Number Bad Checks Probability f(x)

0 .04 .04

1 .06 .10

2 .10 .20

3 .30 .50

4 .20 .70

5 .15 .85

6 .10 .95

7 .05 1.00

b. d. 0.7

e. 0.5

Yes, the sum of the probabilities is equal to 1.

Copyright Cengage Learning. Powered by Cognero. Page 38CH 05 – Discrete Probability Distributions

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: United States – AK – DISC: Probability Distributions

Bloom’s: Apply | Bloom’s: Understand

101. The following probability distribution represents the number of grievances filed per month with the MNM.

Corporation.

x f(x)

0 0.04

1 0.36

2 0.50

3 0.08

4 0.02

a. Determine the expected value of the number of grievances in a month.

b. Determine the variance.

c. Compute the standard deviation.

ANSWER: a. 1.68

b. 0.5776

c. 0.76

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.03 – Expected Value and Variance

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

102. The number of bad checks received per day by a store and the respective probabilities are shown below.

Number of Bad Checks

Received Per Day Probability

0 0.04

1 0.06

2 0.10

3 0.30

4 0.20

5 0.15

6 0.10

7 0.05

a. b. c. What is the expected number of bad checks received per day?

Determine the variance in the number of bad checks received per day.

What is the standard deviation?

Copyright Cengage Learning. Powered by Cognero. Page 39CH 05 – Discrete Probability Distributions

ANSWER: a. 3.66

b. 2.7644

c. 1.6626

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.03 – Expected Value and Variance

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: KEYWORDS: Bloom’s: Apply

United States – AK – DISC: Probability Distributions

103. A cosmetics salesperson, who calls potential customers to sell her products, has determined that 30% of her

telephone calls result in a sale. Determine the probability distribution for her next three calls. Note that the next three calls

could result in 0, 1, 2, or 3 sales.

ANSWER:

x p

0 0.3430

1 0.4410

2 0.1890

3 0.0270

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

104. The following table shows part of the probability distribution for a random variable x.

x f(x)

0 0.2

1 ?

2 0.15

3 ?

4 0.15

a. The mean of the above distribution is known to be 1.8 (i.e.,E(x) = 1.8). Determine f(1) and

f(3).

b. Compute the variance and the standard deviation for the above probability distribution.

ANSWER: a. 0.3 and 0.2

b. Variance = 1.86, Standard deviation = 1.364 (rounded)

POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES

BSST.ASWC.17.05.03 – Expected Value and Variance

:

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: Copyright Cengage Learning. Powered by Cognero. United States – AK – DISC: Probability Distributions

Page 40CH 05 – Discrete Probability Distributions

KEYWORDS: Bloom’s: Apply

105. The following table shows part of the probability distribution for the number of boats sold daily at Boats Unlimited.

It is known that the average number of boats sold daily is 1.57.

x f(x)

0 0.20

1 0.30

2 0.32

3 ?

4 0.05

5 0.02

Compute the variance and the standard deviation for this probability distribution.

Variance = 1.4051, Standard deviation = 1.1854 (rounded)

ANSWER: POINTS: 1

DIFFICULTY: Challenging

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

106. Random variable x has the probability function: f(x) = x/6 for x = 1,2 or 3. The expected value of x is

a. 0.333

b. 0.500

c. 2.000

d. 2.333

ANSWER: d

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s : Apply

107. The number of electrical outages in a city varies from day to day. Assume that the number of electrical outages (x) in

the city has the following probability distribution.

x f(x)

0 0.80

1 0.15

2 0.04

3 0.01

The mean and the standard deviation for the number of electrical outages (respectively) are

a. 2.6 and 5.77

b. 0.26 and 0.577

c. 3 and 0.01

Copyright Cengage Learning. Powered by Cognero. Page 41CH 05 – Discrete Probability Distributions

d. 0 and 0.8

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s : Apply

108. In a binomial experiment the probability of success is 0.06. What is the probability of two successes in seven trials?

a. 0.0036

b. 0.06

c. 0.0554

d. 0.28

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s : Apply

109. A production process produces 2% defective parts. A sample of five parts from the production process is selected.

What is the probability that the sample contains exactly two defective parts?

a. 0.0004

b. 0.0038

c. 0.10

d. 0.02

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s : Apply

110. Assume that you have a binomial experiment with p = 0.4 and a sample size of 50. The variance of this distribution is

a. 20

b. 12

c. 3.46

d. 2.83

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

Copyright Cengage Learning. Powered by Cognero. Page 42CH 05 – Discrete Probability Distributions

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s : Apply

111. The binomial probability distribution is most symmetric when

a. n is 30 or greater.

b. n equals p.

c. p approaches 1.

d. p equals 0.5.

ANSWER: d

POINTS: 1

DIFFICULTY: Moderate

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

112. If one wanted to find the probability of ten customer arrivals in an hour at a service station, one would generally use

the

a. binomial probability distribution.

b. Poisson probability distribution.

c. hypergeometric probability distribution.

d. exponential probability distribution.

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.06 – Poisson Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

113. The _____ probability function is based in part on the counting rule for combinations.

a. binomial

b. Poisson

c. hypergeometric

d. exponential

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.07 – Hypergeometric Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

Copyright Cengage Learning. Powered by Cognero. Page 43CH 05 – Discrete Probability Distributions

114. To compute the probability that in a random sample of n elements, selected without replacement, we will obtain x

successes, we would use the

a. binomial probability distribution.

b. Poisson probability distribution.

c. hypergeometric probability distribution.

d. exponential probability distribution.

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.07 – Hypergeometric Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

115. Experimental outcomes that are based on measurement scales such as time, weight, and distance can be described by

_____ random variables.

a. discrete

b. continuous

c. uniform

d. intermittent

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.01 – Random Variables

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

116. Which of the following properties of a binomial experiment is called the stationarity assumption?

a. The experiment consists of n identical trials

b. Two outcomes are possible on each trial

c. The probability of success is the same for each trial

d. The trials are independent

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

117. A name closely associated with the binomial probability distribution is

a. Bernoulli.

b. de Moivre.

Copyright Cengage Learning. Powered by Cognero. Page 44CH 05 – Discrete Probability Distributions

c. Pareto.

d. Poisson.

ANSWER: a

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.01 – Random Variables

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

118. The use of the relative frequency method to develop discrete probability distributions leads to what is called a

a. binomial discrete distribution.

b. empirical discrete distribution.

c. non-uniform discrete distribution.

d. uniform discrete distribution.

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Remember

119. Experiments with repeated independent trials will be described by the binomial distribution if

a. the trials are continuous.

b. each trial result influences the next.

c. the time between trials is constant.

d. each trial has exactly two outcomes whose probabilities do not change.

ANSWER: d

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

120. The probability distribution for the number of goals the Lions soccer team makes per game is given below.

Number of Goals Probability

0 0.05

1 0.15

2 0.35

3 0.30

4 0.15

The expected number of goals per game is

Copyright Cengage Learning. Powered by Cognero. Page 45CH 05 – Discrete Probability Distributions

a. 2

b. 2.35

c. 2.5

d. 3

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s : Apply

121. The probability distribution for the number of goals the Lions soccer team makes per game is given below.

Number of Goals Probability

0 0.05

1 0.15

2 0.35

3 0.30

4 0.15

What is the probability that in a given game the Lions will score less than 3 goals?

a. .85

b. .55

c. .45

d. .80

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

122. The probability distribution for the daily sales at Michael’s Co. is given below.

Daily Sales ($1,000s) Probability

40 0.1

50 0.4

60 0.3

70 0.2

The expected daily sales are

a. $50,000

b. $55,000

c. $56,000

Copyright Cengage Learning. Powered by Cognero. Page 46CH 05 – Discrete Probability Distributions

d. $60,000

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.03 – Expected Value and Variance

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s : Apply

123. In a Poisson probability problem, the rate of defects is one every two hours. To find the probability of three defects in

four hours,

a. μ = 1, x = 4

b. μ = 2, x = 3

c. μ = 3, x = 4

d. μ = 4, x = 3

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.06 – Poisson Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

124. A binomial probability distribution with p = .3 is

a. negatively skewed.

b. symmetric.

c. positively skewed.

d. multi-modal.

ANSWER: c

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

125. In a binomial experiment consisting of five trials, the number of different values that x (the number of successes) can

assume is

a. 2

b. 5

c. 6

d. 10

ANSWER: c

POINTS: 1

Copyright Cengage Learning. Powered by Cognero. Page 47CH 05 – Discrete Probability Distributions

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.05 – Binomial Probability Distribution

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

126. The weight of an object, measured to the nearest gram, is an example of

a. a continuous random variable.

b. a discrete random variable.

c. a nominal random variable.

d. a mixed type random variable.

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.01 – Random Variables

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Understand

127. The probability distribution for the number of goals the Lions soccer team makes per game is given below.

Number

Of Goals Probability

0 0.05

1 0.15

2 0.35

3 0.30

4 0.15

What is the probability that in a given game the Lions do not score more than 2 goals?

a. 0.20

b. 0.55

c. 1.0

d. 0.95

ANSWER: b

POINTS: 1

DIFFICULTY: Easy

LEARNING OBJECTIVES: BSST.ASWC.17.05.02 – Developing Discrete Probability Distributions

NATIONAL STANDARDS: United States – BUSPROG: Analytic

STATE STANDARDS: United States – AK – DISC: Probability Distributions

KEYWORDS: Bloom’s: Apply

Copyright Cengage Learning. Powered by Cognero. Page 48